Lab Report: Determining Percent Yield in a Chemical Reaction

Purpose:

To find out the percent support of papal bull in the reaction between copper sulfate (CuSO4) and Iron (Fe).

Materials:

Balance

100-mL beaker

250-mL beaker

Bunsen burner

Copper sulfate crystals

Glass stir fence in rod

100-mL graduated cylinder

Iron filings

Ring stand and ring

Wire gauze

Procedure:

1. Record mass of light 100-mL beaker.

2. Add 8.0 grams of copper sulfate crystals to beaker.

3. Add 50.0 milliliters of distilled water to the crystals.

4. confide wire gauze on ring on ring stand, and place the lighted Bunsen burner underneath it. Heat the crystals and water, that do not boil.

5. Stir until all in all dissolved, then suppress burner.

6. Add 2.24 grams of iron filings a little at a time to the hot solution. Allow the beaker to cool for 10 minutes.

7. pelt the liquid into a 250-mL beaker and do not disturb the self-colored at the bottom of the beaker.

8. Add about 10-mL of water to the steady and stir vigorously. Allow the solid to settle and decant again.

9. cattle farm the solid over the bottom and allow to dry.

10. After it is completely dry, mass the beaker and the solid copper. Record.

Data and Observations:

Mass of empty beaker                  67.33 g

Mass of beaker plus copper         69.43 g

unfeigned effect of copper         2.1 g

Expected yield of copper         2.54 g

Percent yield of copper         -17.



32%

Calculations:

        Actual yield of copper = 69.43 g - 67.33 g = 2.1 g

Percent yield of copper = 2.1 g Cu - 2.54 g Cu

                                             2.54 g Cu

Conclusion:

The percent yield of copper is -17.32%.

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